Money
Answer
:
$70
To
maximize the amount of money a person can remove from the box before
getting three of the same bills, let's consider the worst-case scenario.
The person can pick two bills of each denomination without getting three of the same bills.
After picking two $5.00 bills, two $10.00 bills, and two $20.00 bills, they would have a total of:
2 x $5.00 = $10.00
2 x $10.00 = $20.00
2 x $20.00 = $40.00
So,
the most amount of money a person can remove from the box before
getting three of the same bills is $10.00 + $20.00 + $40.00 = $70.00.
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