This
is a classic math problem. Let's denote the youngest son's age as `y`,
the second son's age as `s`, and the eldest son's age as `e`. We can
write the following system of equations:
e = s + 4
s = y + 4
e = 2y
We can solve this system of equations to find the ages of the sons.
Substituting the second equation into the first equation, we get:
e = (y + 4) + 4 = y + 8
Substituting the third equation into the first equation, we get:
y = e / 2
Substituting this expression for `y` into the second equation, we get:
s = (e / 2) + 4
Substituting this expression for `s` into the first equation, we get:
e = ((e / 2) + 4) + 4 = (e / 2) + 8
Solving for `e`, we get:
e = 16
Therefore, the eldest son is `16` years old.
Using the third equation, we can find that the youngest son is `8` years old.
Finally, using the second equation, we can find that the second son is `12` years old.
So the sons' ages are `16`, `12`, and `8` years old.
e = s + 4
s = y + 4
e = 2y
We can solve this system of equations to find the ages of the sons.
Substituting the second equation into the first equation, we get:
e = (y + 4) + 4 = y + 8
Substituting the third equation into the first equation, we get:
y = e / 2
Substituting this expression for `y` into the second equation, we get:
s = (e / 2) + 4
Substituting this expression for `s` into the first equation, we get:
e = ((e / 2) + 4) + 4 = (e / 2) + 8
Solving for `e`, we get:
e = 16
Therefore, the eldest son is `16` years old.
Using the third equation, we can find that the youngest son is `8` years old.
Finally, using the second equation, we can find that the second son is `12` years old.
So the sons' ages are `16`, `12`, and `8` years old.
