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Answer :
Each of the eleven
lines represents a sitting,
each column a table, and each pair of letters a pair of partners.
| A
B — I L |
E
J — G K |
F
H — C D |
| A
C — J B |
F
K — H L |
G
I — D E |
| A
D — K C |
G
L — I B |
H
J — E F |
| A
E — L D |
H
B — J C |
I
K — F G |
| A
F — B E |
I
C — K D |
J
L — G H |
| A
G — C F |
J
D — L E |
K
B — H I |
| A
H — D G |
K
E — B F |
L
C — I J |
| A
I — E H |
L
F — C G |
B
D — J K |
| A
J — F I |
B
G — D H |
C
E — K L |
| A
K — G J |
C
H — E I |
D
F — L B |
| A
L — H K |
D
I — F J |
E
G — B C |
It will be seen
that the letters B, C, D ...L
descend cyclically.
The solution given above is absolutely perfect in all
respects.
It will be found that every player has every other player once as his
partner and twice as his opponent.
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