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Bull's Eye
Thanks
Archery
Answer:
Gloria
= 100
points (four 17's, two 16's)
Peter = 110 points (two 23's, four 16's)
David= 120 points (one 40, five 16's)
AI answer
Let's denote the hits made by each contestant with variables
D1, D2, D3, D4, D5, D6 for David,
P1, P2, P3, P4, P5, P6 for Peter,
G1, G2, G3, G4, G5, G6 for Gloria.
The values of the hits are given by the target values (40, 39, 24, 23, 17, 16).
Given:
- David's total score is 120.
- Peter's total score is 110.
- Gloria's total score is 100.
We can set up the following equations based on the scores:
1. D1 + D2 + D3 + D4 + D5 + D6 = 120
2. P1 + P2 + P3 + P4 + P5 + P6 = 110
3. G1 + G2 + G3 + G4 + G5 + G6 = 100
Now, we know the values of the hits:
- Bull's eye (40 points) was hit once by one of the contestants.
Let's assume David hit the bull's eye, so D1 = 40.
- The remaining five hits for each contestant can take values from the target values (39, 24, 23, 17, 16).
Let's find the possible combinations:
1. David: 40, 39, 24, 23, 17, 17 (120 points)
2. Peter: 39, 24, 23, 17, 17, 17 (110 points)
3. Gloria: 24, 23, 17, 17, 17, 2 (100 points)
These are the possible hits for each contestant that satisfy the given conditions.
PS:
Can you
find another way?
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